Simplification of Complex Fractions

[bacchae23]

Hey, there. Algebra 2 student in high school, currently working on rational expressions and the like

Comments

[korean_guy_01]

For 2/x and 3/(x-1), I would get a common denominator of x(x-1). So, you'll have [2(x-1)+3x]/[x(x-1)]. Simplify the numerator.

If you have [a/b]/[c/d], that is equivalent to [ad]/[bc].

Also, I would factor 2x-2.

[chipuni]

Here's a different set of help...

The fraction a / b can be thought of as a product between a and the inverse of the denominator (1 / b).

That doesn't look like much, until you realize: that idea works, even if a and b are themselves fractions.

So, if you have something like (w / x) / (y / z ), you can multiply the numerator with the inverse of the denominator to get (w / x) * (z / y). That makes (w * z) / (z * y).

Hope this helps...