puzzle!!

Dec 31, 2005 16:55

have fun solving this. Took me a while ( Read more... )

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Comments 16

hermitt January 1 2006, 01:26:45 UTC
three questions to each or three total?

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allninjasgo____ January 1 2006, 01:35:02 UTC
3 total

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allninjasgo____ January 1 2006, 01:35:10 UTC
um?

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hermitt January 1 2006, 02:11:44 UTC
ha. people have yet to solve it. and this isn't that hard as the billard ball problem. not nearly.

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geinsei January 1 2006, 19:17:38 UTC
Not 3 to all of them, 3 individual questions to one of them. Also, it wouldn't work anyway, because the random man might lie every time or tell the truth everytime.

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allninjasgo____ January 1 2006, 20:19:30 UTC
yeah, sam's right. and carson, if this is soooo much easier, solve it.

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blowfishkill January 2 2006, 01:22:00 UTC
Here's what Colin and I got:

1) Would 2 always lie?

2) Would 3 always lie?

3) Does 2 tell truth and lies?

So, if you ask this question to either the truth teller or the liar, you can figure it out. BUT if you ask the rondomizer, he could always tell the truth, or always tell lies or mix them up. To solve this question, you would have to be able to ask more than one of the men.

HA!

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geinsei January 2 2006, 04:58:32 UTC
Allie, you are allowed to ask different people questions.

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blowfishkill January 2 2006, 11:38:35 UTC
"Not 3 to all of them, 3 individual questions to one of them." Quoth YOU idiot.

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allninjasgo____ January 2 2006, 21:51:18 UTC
you can ask THREE questions total. you can ask any of these questions to any of the three people.

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