Changing Base

Jun 01, 2005 20:55

Happy June everyone! I apologize that this one is late. It's an easy one.

What is log base two of 9 in base ten? Basically (hahaha) how do you change a logarithmic statement from base two to base ten?

Note: re-posted from my old OO.net blog

questions, oo.net, backlog, math

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Comments 3

reverdybrune April 28 2006, 04:00:58 UTC
realitycheck44 (on OO.net) commented:

Do 10^(log2(9), which = about 3.1699)

You get 1478.85 or about 1479.

The answer is log10(1479).

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reverdybrune April 28 2006, 04:01:19 UTC
There is an easier and more accurate method, but perhaps I did not make my question clear. I was probing for an exact answer. There is a formula known as the change of base formula. It goes like this. log a (b) = log x (b) divided by log x (a)

So log 2 (9) = log 10 (9) divided by log 10 (2)

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reverdybrune April 28 2006, 04:01:53 UTC
realitycheck44 (on OO.net) commented:

Yeah, that's not what I thought you were asking. The funny thing is I used that formula to find what log2(9) was. I just did a little extra work. Oh well...

Zak

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