According to the Heisenburg Uncertanty Principle, how exact must you know the speed of a truck so that its position is so uncertain that it could be in either Pennsylvania or Mexico?
It can already be in Pennsylvania or Mexico. The uncertainty principle gives minimum uncertainty. Hell, I don't know where the truck is. It could be anywhere.
The uncertainty principle (or at least the form we want) gives us
delta X * delta p > h-bar / 2
where delta X is the uncertainty in the location and delta p is the uncertainty in the momentum. We also have delta p = m * delta v, where m is the mass and delta v is the uncertainty in the momentum.
Assume that it's 5000 (about 75*10^6 m) miles from PA to Mexico and that the truck weighs 10 tons, which is roughly 10,000 kg). h-bar is about 10^-34 J s.
This gives us roughly
delta v > h-bar / (2 * m * delta x) > 10^-34 / (150 * 10^6 * 10^4) =~ 10^-46 m/s
Now, there are some subtleties about the inequality, but what we're interested in here is the case when both sides are almost equal. So what we end up with is that if you measure the speed of the truck with a precision of 10^-46 m/s, then its position will be uncertain to about the distance between PA and Mexico.
Hopefully that was somewhat enlighting - feel free to ask questions.
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In that case, I will bow down to the superior knowledge of actual physicists, because I would never do anything that I'm not qualified to do.
::looks at everything she's been doing at work this summer::
Oh. Right. Nevermind, then.
The equation was something like ΔpΔx ≥ η / 2, so the obvious answer is moo. ::sits and waits for her boss to tell her otherwise::
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The uncertainty principle (or at least the form we want) gives us
delta X * delta p > h-bar / 2
where delta X is the uncertainty in the location and delta p is the uncertainty in the momentum. We also have delta p = m * delta v, where m is the mass and delta v is the uncertainty in the momentum.
Assume that it's 5000 (about 75*10^6 m) miles from PA to Mexico and that the truck weighs 10 tons, which is roughly 10,000 kg). h-bar is about 10^-34 J s.
This gives us roughly
delta v > h-bar / (2 * m * delta x) > 10^-34 / (150 * 10^6 * 10^4) =~ 10^-46 m/s
Now, there are some subtleties about the inequality, but what we're interested in here is the case when both sides are almost equal. So what we end up with is that if you measure the speed of the truck with a precision of 10^-46 m/s, then its position will be uncertain to about the distance between PA and Mexico.
Hopefully that was somewhat enlighting - feel free to ask questions.
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<3
Gold star, physics man!
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