Something that's fun to do is to write numbers in "base prime," in which the digits are the factors:
base-10
factorization
base-P
1 10
2 21
3 310
4 2 22
5 5100
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0 is not-a-number in base P, as far as I know... sort of like an infinity. You can, of course, use a limit to get to it, though. If you have a "negative digit", for example, {2,0,-3}, you would have 5^2*3^0*2^-3 = 25/8. So, lim[k->Inf](P{-k}) = 0.
Hmm, you mean 2p mul'd 3p times? In other words, 4 mul'd thrice? Well, 2p is the identity function, so it'd just be 2p... I'm guessing you meant something else, though---clarify?
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You can, of course, use a limit to get to it, though.
If you have a "negative digit", for example, {2,0,-3}, you would have 5^2*3^0*2^-3 = 25/8.
So, lim[k->Inf](P{-k}) = 0.
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Well, 2p is the identity function, so it'd just be 2p...
I'm guessing you meant something else, though---clarify?
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I haven't been awake very long, excuse my stumbling-abouts ;P
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