We want the probability that given a random 10 digit number, it will contain EACH of (as consecutive left to right digits)
-- a 1 digit prime -- a 2 digit prime ... -- a 6 digit prime
The probability that a random 6-digit number is prime is approximately 8.7%. The probability that at least one of 4 6-digit numbers is prime is thus about 31%.
For 5 5-digit numbers a similar calculation gives about 72%.
So without continuing I'd guess we'd be looking at something like a 15% chance, ignoring issues of independence, which doesn't warrant a 'zounds'.
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-- a 1 digit prime
-- a 2 digit prime
...
-- a 6 digit prime
The probability that a random 6-digit number is prime is approximately 8.7%. The probability that at least one of 4 6-digit numbers is prime is thus about 31%.
For 5 5-digit numbers a similar calculation gives about 72%.
So without continuing I'd guess we'd be looking at something like a 15% chance, ignoring issues of independence, which doesn't warrant a 'zounds'.
Once again, probability triumphs over intuition.
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