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[ethnic]

fuck, how dead is livejournal?

Comments

[mitchell_109k4]

pretty dead.
were you hoping to procrastinate?
have you finished exams yet or what? i want to come visit you at work/home.

[ethnic]

yes i was! like always! we only have one comupter with the internet in my house right now so i was pretty desperate
it was nice to hear from you this morning; im glad i didnt watch it i would have been devastated for either party that didnt do well
and today it seems there would have been tears streaming from my little grb (checkered crest thing that is on everything)

[imgonnasnap]

i have some/two clips of your band playing on friday, i can upload em if you want.

[ethnic]

yeah thanks that would be good
i was so embarassed on friday; the keyboard sound fucked up and the fact that we got asked to come back to school just to be forced to play under pukeys band was quite degrading
i hope you had fun on the night

[imgonnasnap]

here's the shorter clip:

http://www.sendspace.com/file/uu7kbc

well think of it this way.. you've played at hopetoun, while they've played at........ armadale.

yeah it was mad, red riders went off.

i saw the frustration on your face haha. i don't think people noticed though, so it's okay.

[roastbeefcombo]

that's because it's all about fucking ghey myspace. it's so much easier to whore on there. it's disgusting.

[ethnic]

my space! i have a my space but its the ugliest thing ever because i dont know how to use it or make it look better. also i cant bring myself to whore on there because i have too many emotional connections with lj.
shellz tells me you got us on mylk door??? yay!

[precursory]

*deadjournal

[ethnic]

i was going to pay out your name in some way but i cant think of anything
*****

[anangrymoose]

you're dead

[ethnic]

microeconomics is dead

i wish

[anangrymoose]

Show that if a < b, then (b - a)/(1 + b^2) < tan^-1(b) - tan^-1(a) < )(b - a)/(1 + a^2)

Let f(x) = tan^-1(x)
so f'(x) = 1/(1 + x^2)

By the Mean Value Theorem, if a < b, then there is some point c (a < c < b) where f'(c) = (f(b) - f(a))/(b - a)

1/(1 + c^2) < (tan^-1(b) - tan^-1(a))/(b - a)

But a < c < b
so a^2 < c^2 < b^2
so 1 + a^2 < 1 +c^2 < 1 + b^2
so 1/(1 + b^2) < 1/(1 + c^2) < 1/(1 + a^2)

Therefore, 1/(1 + b^2) < (tan^-1(b) - tan^-1(a))/(b - a) < 1/(1 + a^2)
(b - a)/(1 + b^2) < tan^-1(b) - tan^-1(a) < (b - a)/(1 + a^2)

Q E FUCKING D CANAGASABEY