General Formula

Mar 01, 2008 18:58

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joshua_green March 2 2008, 02:31:07 UTC
If you are trying to find the Taylor series for ƒ(x), there are easier ways than taking a bunch of derivatives.  Start with the series for 1/(x - 1) and go from there.

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joshua_green March 2 2008, 02:32:22 UTC
And if you really need all the derivatives, begin with a partial fraction expansion.

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soccer_gal March 2 2008, 02:45:07 UTC
Well I was just asked to come up with a general formula for 1/(x^2-1).
And I have never heard of the Taylor series before but I just googled it.

So..I didn't understand what you meant by starting with the series for 1/ (x-1)...but is this what you mean I should do with regards to the Taylor series I(and from what I got from wikipedia about the Taylor series)...
1/(x-1) + 1/(x-1)^2 + 1/ (x-1)^3 ????

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joshua_green March 2 2008, 02:50:12 UTC
If you know the Taylor series for 1/(x - 1), you can easily find the Taylor series for 1/(x2 - 1).  However, if you're not looking for the Taylor series, you can ignore that piece of "advice."  The partial fraction expansion would be a better route.

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alteredmana March 2 2008, 04:11:01 UTC
I second green's response above-- use partial fraction decomposition and it will be expressible as the sum or difference of two easily-to-infinitely-differentiate rational functions.

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