If you are trying to find the Taylor series for ƒ(x), there are easier ways than taking a bunch of derivatives. Start with the series for 1/(x - 1) and go from there.
Well I was just asked to come up with a general formula for 1/(x^2-1). And I have never heard of the Taylor series before but I just googled it.
So..I didn't understand what you meant by starting with the series for 1/ (x-1)...but is this what you mean I should do with regards to the Taylor series I(and from what I got from wikipedia about the Taylor series)... 1/(x-1) + 1/(x-1)^2 + 1/ (x-1)^3 ????
If you know the Taylor series for 1/(x - 1), you can easily find the Taylor series for 1/(x2 - 1). However, if you're not looking for the Taylor series, you can ignore that piece of "advice." The partial fraction expansion would be a better route.
I second green's response above-- use partial fraction decomposition and it will be expressible as the sum or difference of two easily-to-infinitely-differentiate rational functions.
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And I have never heard of the Taylor series before but I just googled it.
So..I didn't understand what you meant by starting with the series for 1/ (x-1)...but is this what you mean I should do with regards to the Taylor series I(and from what I got from wikipedia about the Taylor series)...
1/(x-1) + 1/(x-1)^2 + 1/ (x-1)^3 ????
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