1. The oblique asymptote is x+1 seeing as you simply divide the top by the bottom. 2. Geometry+ algebra= too lazy to do at `10:28 in the morning. 3. Similar question on our exam last year! use the sin/cosine rule, whichever seems convienient (use sin actually seeing as you only need one length and you know the angle must be acute)
I know that, but the asymptote is the one that's the.....hmm......the number that's in it completely! The thing on top of the dividing symbol. That's terribly comprehendable, don't you think. 6x-4 is the leftover, that's why we put it over x^2-x and I graphed it.....and graphs win!
OOops MY bad! see I've been hallucinating recently I've dreamed things that actually haven't happened so I tend to doubt that I actually did them in real life now....like saying lunch balconey today? oops. I apologize profusely. I really am very, very sorry.
2. Geometry+ algebra= too lazy to do at `10:28 in the morning.
3. Similar question on our exam last year! use the sin/cosine rule, whichever seems convienient (use sin actually seeing as you only need one length and you know the angle must be acute)
Hopefully that helped you out!
Reply
(x^3+5x-4)/(x^2-x) = x+1 + (6x-4)/(x^2-x).
Check it.
Reply
That's terribly comprehendable, don't you think.
6x-4 is the leftover, that's why we put it over x^2-x
and I graphed it.....and graphs win!
Reply
Reply
Reply
Reply
Reply
I actually checked in last year's math notes
it's x-1!!!
And x ordiantes =abisscae..however you spell them, k8t!
Reply
Reply
Reply
Reply
Reply
see I've been hallucinating recently
I've dreamed things that actually haven't happened
so I tend to doubt that I actually did them in real life now....like saying lunch balconey today? oops. I apologize profusely. I really am very, very sorry.
Reply
Reply
Reply
Leave a comment