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sexytrevy
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calculus
Question
May 09, 2007 16:50
Hi, this should be easy but i'm just unsure (
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hawkington
May 9 2007, 07:25:51 UTC
why are you differentiating with respect to the dummy variable t?
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sexytrevy
May 9 2007, 07:29:02 UTC
Um, I said integrating with respect to t, following that differentiating to x. Is that what you mean?
The question is:
Find the derivatives of the following functions with respect to x: here a is an arbitrary (fixed) real number.
F[x] = t^3 . dt {a -> x^3}
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hawkington
May 9 2007, 07:33:33 UTC
just integrating with respect to t then differentiating that with respect to x I get 3x^11
What is all this? All you need to do is use the FTC once. You used the FTC wrong, you'll need to review it.
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hawkington
May 9 2007, 07:36:35 UTC
Hmmm, well FTC is stated differently. There is a corrolary for variable limits of integration, you'll need to review that.
Another route is to write F(x) explicitly in terms of x and a and then to differentiate that with respect to x.
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sexytrevy
May 9 2007, 07:37:51 UTC
The other route is what I thought I did the second way and ended up with 3x^11...
I'm really not sure what i'm doing wrong, I thought I followed the example exactly...
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hawkington
May 9 2007, 07:41:06 UTC
You confused me originally. Your work is right. My fault anyways.
There's a corrolary that says the derivative of F(x)=int(f,u(x)->v(x)) is f(v(x))*v'(x)-f(u(x))*u'(x). If you try this you will get the same answer.
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sexytrevy
May 9 2007, 07:42:01 UTC
Thanx, i'll have a go that way aswell.
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The question is:
Find the derivatives of the following functions with respect to x: here a is an arbitrary (fixed) real number.
F[x] = t^3 . dt {a -> x^3}
Reply
What is all this? All you need to do is use the FTC once. You used the FTC wrong, you'll need to review it.
Reply
Another route is to write F(x) explicitly in terms of x and a and then to differentiate that with respect to x.
Reply
I'm really not sure what i'm doing wrong, I thought I followed the example exactly...
Reply
There's a corrolary that says the derivative of F(x)=int(f,u(x)->v(x)) is f(v(x))*v'(x)-f(u(x))*u'(x). If you try this you will get the same answer.
Reply
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