Question

May 09, 2007 16:50

Hi, this should be easy but i'm just unsure.
We're required to find the derivative with respect to x of F[x] = t^3 dt, from {a -> x^3)
Using the fundamental theorem of calculus I end up with (3x^2)*(x^9 - a^3) and just integrating with respect to t then differentiating that with respect to x I get 3x^11

Could someone please work through the question and help? Thanx
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