rotfl

Jan 24, 2008 11:20

e^x and a constant were walking down the street. Suddenly, the constant notices a differential operator walking along the other side of the street. "Oh, no!" exclaims the constant. "I've got to run away! You've got to hide me! There's a differential operator... he could reduce me to nothing!" "Hmmmph," came the haughty reply. "I'm e^x. He can't do ( Read more... )

lol

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bluesmoon January 26 2008, 05:11:10 UTC
e^x is constant for d/dy since x is non-changing.

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colono January 26 2008, 08:43:39 UTC
Yeah misread d/dy as dx/dy. Blame it on my lack of sleep when reading it. Hence, was just writing a dumb comment. Btw, this has been slash-dotted earlier, with an integration version also doing rounds.

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