Jul 29, 2006 17:53
(1) let x = 2+2
(2)[multiply by x-1] x(x-1)=(2+2)(x-1)
(3) x^2 -x = 2x+2x-2-2
(4)[subtract 3x] x^2-4x=x-4
(5)[multiply by x-5] (x-5)(x^2-4x)=(x-5)(x-4)
(6)x^3-9x^2+20x=x^2-9x+20
(7)x(x-4)(x-5)=(x-4)(x-5)
(8)[divide by x-4] x^2-5x=x-5
(9)[add 4x] x^2-x=5x-5
(10)x(x-1)=5(x-1)
(11)[divide by (x-1)] x=5
And we started with x=2+2, therefore 2+2=5
Interesting huh :p
-Efren.