Toilet logic

May 24, 2006 18:05

Today, on Math with Marjorie: Why The Toilet Seat Should Remain Down

Given: There are two genders (for the sake of simplicity)-- M and F. There are also two possible outcomes when using a toilet. Let's call them outcome 1 and outcome 2.

Now, take the fact that both genders produce equal amounts of outputs 1 and 2. Therefore, the following combinations are possible:

M1
M2
F1
F2

Now let's look at ratios. The seat only has to be up for the outcome "M1". For all other outcomes (M2, F1, and F2), the seat must be down.

Therefore:

M2+F1+F2 = 75%
M1 = 25%

75% is the majority.

Now we take into account the number of each gender (M or F) living in the house. For example, a family such as the Hallorans, with three women and one man.

(F1 + F2) X 3 = 6 possible outcomes (two for each woman in the house)
M2 X 1 = 1 outcome
M1 X 1 = 1 outcome

Note that M1 is the only outcome which yields a raised toilet seat. In this scenario, the ratio is 6+1/total outcomes, or 7/8.

7/8 X 100 = aprox. .875

CONCLUSION:

In a family with three women and one man, the percentage of time the toilet seat needs to be down is aprox. 88%. The toilet seat only needs to be up 22% of the time.

THUS: The toilet seat should always remain down in between uses. The only exception to this rule is if there are NO females living in the house.

Girls still don't poop, though.

speaking of toilets, math with marjorie

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