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sombragris
Not that anyone who reads this would care,
Jun 21, 2007 17:43
but I just stumbled upon another nifty property:
In the expansion of (x1 + x2 + x3 + x4 + ... + xi)n
the coefficient of the term with (x1a1)(x2a2) ... (xiai)
equals n!/((a1!)(a2!)...(an!))
(thanks,
meritite
:D)
math
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