Feb 09, 2008 14:45
Hey flist,
how would you solve 2we^(w^2)-2e^w=0?
(And just to make sure, it is the f'(w) of a function f(w)=e^(w^2)-2e^w, right?)
I hope there's at least one math geek among you :S
ps. I usually love this kind of math problems, but for some reason now I can't do it :(
help,
school,
math
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Looking through the other comments, my method was much the same as shown on her picture, with a similar result. The only solution I could find algebraic was w=1 - which could very well be the only solution. I then stuck into into my maths package on my laptop. It's possible that I coded it wrong, but either way it didn't come out with anything more helpful so we could well be right.
If you're using that eqn to find max/min, you're not expecting a whole string of answers for an eqn involving e.
Sorry I couldn't be of more help
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Yup, it is. So, did you have some actual way for getting it? Or was it just a conclusion reached by looking at it, or something?
Thank you, in any case! ^^
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Let y=e^w cos it makes it easier to look at
2wy^w-2y=0
Divide by 2
w(y^w)-y=0
Take out a factor of y
y(wy^(w-1)-1)=0
So either y=0 or w(y^(w-1))=1
Replace y by e^w
e^w=0 never happens, so no solutions from this factor
Rearranging the other equation
y^(w-1)=(1/w)
By recognition, if you take w=1, y^(w-1)=1 because anything to the power 0 is equal to 1. Also 1/1=1, so w=1 is a solution.
I've played around with the second factor some more and can tell that there aren't any other integer solutions but off the top of my head I can't prove that there aren't any non-integer solutions.
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Still, good to know that we agree :D
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Huge thanks for all your help! :)
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No problem with the help - aiwritingfic said 'maths' and I was over here like a shot :D
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