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Aug 31, 2004 14:57

Jamie (or anyone else who knows what this means) first question: what does this mean?
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darth_phoenix August 31 2004, 12:29:41 UTC
3rd derivative of y with respect to x, any other variables are considered constants (although it doesn't matter here since you only HAVE one variable).

answer is below... if you have white background, highlight to read...

Mathematica says:
-384*(3x-4)/(4x+2)^4+288/(4x+2)^3

for an input of "D[(3x - 4)/(4x + 2), {x, 3}]", if that helps any. ;)

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perfectspring September 1 2004, 10:07:14 UTC
I can't get the first half to save my life... is this the right second derivative?
(288x-32)/(4x+2)^3

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darth_phoenix September 1 2004, 11:06:14 UTC
First derivative: 11/(2[2x+1]^2)

Second derivative: -22/[2x+1]^3

Third derivative: 132/[2x+1]^4

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perfectspring September 1 2004, 13:57:01 UTC
er... i think i must have forgotten how to find derivatives :-/

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darth_phoenix September 1 2004, 21:30:50 UTC
Yeh I know... but they're the same thing, just simplified. I forgot to simplify it last time. And (2x+1) is half of (4x+2), so I'm sure somet cancelled.

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perfectspring September 2 2004, 13:17:48 UTC
yeah, i finally got that... and realized that i was putting + instead of - :-P... but i think i finally remembered everything, and i STILL can't see how the second diff is negative.. i have the right answer, but it's positive

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darth_phoenix September 2 2004, 13:19:54 UTC
It's 'cause you have a negative power of x.. so you multiply by the negative power when you differentiate. Thus making the second differential negative and the third positive.

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perfectspring September 2 2004, 20:05:15 UTC
OHHHH duh... i'm going to be in trouble when school starts :-/

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