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Jun 25, 2008 19:46

I NEED HELP WITH CHEMISTRY, I WOULDN'T BE POSTING THIS IF I WEREN'T DESPERATE. I HAVE TO DESIGN A LAB REPORT/EXPERIMENT TO THIS PROBLEM:

As an energy conservation method you decide to turn your water heater to 55ºC. The only thermometer available is unmarked above 40ºC. Using your 40ºC thermometer and any other materials on your lab, determine the ( Read more... )

help, school

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potterchick958 June 26 2008, 00:44:00 UTC
I know nothing about Chem. I nearly failed it when I took it 2 years ago. I'm sorry, darling.

Good luck!

Love, Amanda

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zazenica June 26 2008, 04:24:26 UTC
Do you have any chemicals in the lab you know will precipitate in and out of solution at temperatures between forty and fifty-five degrees C, or any combinations of chemicals that will precipitate at known temperatures and concentrations ( ... )

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potterchick958 June 26 2008, 04:27:58 UTC
I'm guessing that you wanted this to go to Sharon. lol

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zazenica June 26 2008, 04:29:42 UTC
Eek. Yes. :P Sorry, I just clicked on the first "reply" link I saw...

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potterchick958 June 26 2008, 04:43:49 UTC
lol no worries. :D

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zazenica June 26 2008, 04:28:53 UTC
...Now that I think about it, that second suggestion is pretty sketchy, and I'm assuming you guys are allowed to treat water vapor as an ideal gas (if you weren't, they'd have to provide you with about fifty different tables of thermodynamic data)...

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twinsuns June 26 2008, 12:31:34 UTC
There's the science that I lacked! ♥

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zazenica June 26 2008, 15:23:30 UTC
Except I just realized there's one problem with the gas law suggestion...the mass of the vapor is unknown if you use PV = nRT. O_o If you use a specific version of the gas law, you can correct for that...but I'm wondering how much ideal gas stuff anyone does before they get to college and take thermo. Heh.

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zazenica June 26 2008, 15:36:02 UTC
Haha, Sharon, you could also try a calorimetry experiment...at this point I don't know how good any of my suggestions are, but what if you had a cup of water of known mass and temperature (make it cold so you don't get any thermometer readings above 40C later on), a cup of water of known mass and the unknown temperature, and then measured the heat transfer between the two of them using q=mc(T2-T1) as the two cups approached equilibrium? As long as there's enough water in the first cup, you'd be able to measure the temperature change of the first cup of water with a thermometer. This will give you the amount of energy lost from the water in the water heater, which will allow you to determine the temperature change. Use the equilibrium temperature of the cups as one of your temperature values for the water in the heater, plug the energy value (q) into the equation, and solve for your second temperature value. This will be the temperature of the water being heated.

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latine June 27 2008, 00:17:22 UTC
Jenna! Wow. Thank you so much. It's horrible that I saw this after I have handed the work in (worst I've ever done), but yes, you were right. The easiest way was the Q = m.cw.change in T but I forgot about that.

Many thanks, anyway!

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zazenica June 28 2008, 16:44:18 UTC
Eek. Sorry I didn't comment sooner...? Haha. Well, good luck with everything, and I'm sure you'll do fine. :) Cheers!

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