Mi stori
Many have heard me bitch for the past few days about having no motivation to do anything at all, ect. So I decided to write a story for my, and possibly your enjoyment.
Here's how it happened..
Saturday.
"Play. Wanna come?"
"Sure!"
"Ok."
Desk.
"15 bucks please."
"15 bucks! Jeez."
"Only have 10 bucks.. 5 bucks please?"
"Bah!"
Theatre."Hi ( Read more... )
Here's how it happened..
Saturday.
"Play. Wanna come?"
"Sure!"
"Ok."
Desk.
"15 bucks please."
"15 bucks! Jeez."
"Only have 10 bucks.. 5 bucks please?"
"Bah!"
Theatre."Hi ( Read more... )
Ok here is how it really went down.
We start this whole deal off with 4 different groups of people (3 groups of 1 and 1 group of -more than 1-)
Lets call them P(more than 1 person),Q,S,A
Lets GET STARTED!
0. A bunch of whack shit happens then:
1. P,Q, and S "Rejoice"
2. P goes home
3. Q and S "Rejoice"
4. S goes home.
Make the triangle PQS and find the tangent of the acute angle of the triangle. Then disregard that number.
This brings us to the Persons telling persons ordeal.
1. Q talks to S.
2. S tells Q that S needs to talk to A.
3. S seems to be confused because S needs to deal with Q and A.
This equation forms the love triangle QSA. Classic.
Tomorrow S should resolve the situation involving the Q&A. (same brilliant punchline)
So actually the whole situation is quite simple.
Q is now waiting for S to call back, obviously hoping that the angle SQA is larger than the angle SAQ.
Q should also be looking at the dr/dt of the relationship between Q and S. Is the derivitive of thier relation large enough to overpower the constant relation that Q already had with A? We can call the relation Q->S X, and the relation Q->A Y. Also take note that in order to find the relation of Q->S we had to take the dr/dt and put that into the equaiton of thier relation, in this case dr/dt x the time they have know eachother (T). so the final equation that Q should be looking at is this:
(dr/dt)T > Y. (basically X>Y) If that statement is true, then Q is happy.
Also there is another factor that must be considered. S might not want to have any relation between anyone at T=now. This will introduce another variable, namely B. It can be a 0 or a 1 depending on what S's actual choice is. Here is a modified equation:
X * B > Y * B.
This equation will much beter suit the domain of the question. Basically this says. If A->S is larger than Q->S AND B = 1 then Q will be happy. So if its >, A wins, < Q wins, or = means everyone looses.
Good luck Q.
Thank you and good night.
ps. ashi - algebra, geometry, trigonometry, and calculus.
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It's way too early in the morning for those! ;)
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