(no subject)

May 23, 2009 11:58

Sean is this correct? You seem to know what you are doing and then some, so I'd truly appreciate it if you'd check my work and confirm I'm on the right track....or redirect me if I'm truly off track.

Last year at the Independent Learning Centre, a group of 48 students enrolled in mathematics, French, and physics. Some students were more successful than others: 32 passed French, 27 passed physics, and 33 passed mathematics; 26 passed French and mathematics, 26 passed physics and mathematics, and 21 passed French and physics; 21 passed French, mathematics, and physics. How many students passed one or more of the subjects?

Imagine the same Venn as before but Math is A, French is B and Physics is C

A + B + C = 48
D = 33 - (G+J+I)= 2 or the number of people who didn’t pass Mathematics.
E = 32 - (G+J+H)= 6 or the number of people who didn’t pass French
F = 27 - (I+J+H) = 1 or the number of people who didn’t pass Physics

(G + J = 26 or the number of people who passed French and Mathematics
I + J = 26 or the number of people who passed Physics and Mathematics
J + H = 21 or the number of people who passed French and Physics
J = 21 or the number of students that passed all three)

Replace J in the equations and solve
G = 5
H = 0
I =5
J = 21
∴ adding all the students that did not pass and subtracting them from the number of students enrolled will find out how many passed one or more classes. 48 - (D or 2 + E or 6 + F or 1) ∴ 39 students passed one or more classes.
Previous post
Up