(no subject)

May 07, 2006 10:29

Stupid physics review books...

part of a problem: find the maximum height of an object whose vertical position is described by the function y(t)=1/2t^2-4t
a) 0 s
b) (8)^1/2 s
c) 4 s
d) (2)^1/2 s
e) 2 s

ok... piece of cake

1) d/dt[1/2t^2-4t] = t-4
2) sign chart

--|--
- 4 +

wtf
3) second derivative test: d/dt[t-4] = +1

WTF
*checks back of book*

their explanation:
"The answer is C. The maximum y-coordinate occurs when Vy=0.
Vy = d/dt[1/2t^2 - 4t] = t-4
0 = t-4 -> t=4 s"

Idiots, maximum my ass. Way to correctly teach calculus.

In other news, i'm going to fail both the ap physics and ap chem tests. huzzah?

Sami
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