warning: comparison between signed and unsigned integer expressions
Dear Lazyweb,
Philosophically, why is it a warning to test equality between signed and unsigned integer expressions in C++? Is it a performance issue (i.e., u==i would become bitwise_equal(u, i) && i >= 0)? Is it just that it thinks mixing signedness is a bad idea?
Philosophically, why is it a warning to test equality between signed and unsigned integer expressions in C++? Is it a performance issue (i.e., u==i would become bitwise_equal(u, i) && i >= 0)? Is it just that it thinks mixing signedness is a bad idea?