MATHS TEACHER!
AAAAAHHHHHHHH!!! *deep breath* ok so my maths teacher is a complete fu*king cu*t!! In desperate need of help!! i'm sooo confused!!
question
A--------B--------C
The distance from A to B is 1000m and the distance from B to C is also 1000m. A train is traveling at a constant acceleration of 2m/sxs. The train takes 30s to go from point A to point B and 60s from point B to point C.
My question is how does it take twice the time to travel the same distance if the train is accelerating and :. gaining speed?????? Is the train changing direction between B and C??? (it can't be cos the velocity isn't 0 if you put it into an eqn). How can the velocity change if the acceleration is constent and positive, and the train doesn't change direction? U = 0m/s
Also consider the movement of a car...
A--------C--------B
Ok so the car's going from A to B with a constant decceleration of -2m/sxs, and then doubles back on its self to point C after 5s. Then at point B the velocity would be 0!! ok so i know is's slowing down and then turns round and continues to slow down but that means it would have to stop at B and the velocity = 0. If the velocity = 0 then in my opinion the car has to speed up again to be able to slow down?? does it not???? how can you continue to slow down when your stopped?????
Ok so i really don't understand!! yes i'm prob wrong but can someone please expain how the bloody thing works cos when i asked the teacher he told me i was holding up the class... oops! And julie HOW DARE YOU DROP YOUR RULER!!!
Aparently i had an after school detention yesterday... oops i didn't know!! what for anyway?? prob for the whole late turning up for school thing... that would be why they sent the note home... oops!
question
A--------B--------C
The distance from A to B is 1000m and the distance from B to C is also 1000m. A train is traveling at a constant acceleration of 2m/sxs. The train takes 30s to go from point A to point B and 60s from point B to point C.
My question is how does it take twice the time to travel the same distance if the train is accelerating and :. gaining speed?????? Is the train changing direction between B and C??? (it can't be cos the velocity isn't 0 if you put it into an eqn). How can the velocity change if the acceleration is constent and positive, and the train doesn't change direction? U = 0m/s
Also consider the movement of a car...
A--------C--------B
Ok so the car's going from A to B with a constant decceleration of -2m/sxs, and then doubles back on its self to point C after 5s. Then at point B the velocity would be 0!! ok so i know is's slowing down and then turns round and continues to slow down but that means it would have to stop at B and the velocity = 0. If the velocity = 0 then in my opinion the car has to speed up again to be able to slow down?? does it not???? how can you continue to slow down when your stopped?????
Ok so i really don't understand!! yes i'm prob wrong but can someone please expain how the bloody thing works cos when i asked the teacher he told me i was holding up the class... oops! And julie HOW DARE YOU DROP YOUR RULER!!!
Aparently i had an after school detention yesterday... oops i didn't know!! what for anyway?? prob for the whole late turning up for school thing... that would be why they sent the note home... oops!